Re: [Cal_Boats] tankage

(6.5+10.5)/2x13.5x48/1728x8.48=27.03 John R Thorn 479.263.6448

Correction there is 7.48 gal per cubic foot not 8.48 which would make capacity 23.84 gallons. Old timers moment John R Thorn 479.263.6448

And you want to multiply by the base which is less than 13.5. On Dec 29, 2016 3:54 PM, "John Thorn th… [at] att.net [Cal_Boats]" < Ca… [at] yahoogroups.com> wrote: Correction there is 7.48 gal per cubic foot not 8.48 which would make capacity 23.84 gallons. Old timers moment John R Thorn 479.263.6448 <(479)%20263-6448>

18.54 gallons less air space On Thursday, December 29, 2016 5:54 PM, "John Thorn th… [at] att.net [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: Correction there is 7.48 gal per cubic foot not 8.48 which would make capacity 23.84 gallons. Old timers moment John R Thorn 479.263.6448

OK, let's analyze it. Consider the end. It is a rectangle of height 6.5 and of unknown length (for now). And a triangle with a height of 4 and a hypothesis of 13.5. Solving for the missing length we get sqrt(13.5^2 - 4^2) = 12.894. So the area of the triangle is 25.79. The rectangle is 83.811. The area of the end is 109.6. This times 48 is 5260.73 sq inches. Now, using THIS <http://letmegooglethat.com/?q=convert+5260.73+cubic+inches+to+gallons> link, I get 22.77372294, which is pretty close to what I said before. On Thu, Dec 29, 2016 at 4:22 PM, Tom Vandiver bs… [at] yahoo.com [Cal_Boats] <Ca… [at] yahoogroups.com> wrote: > > > 18.54 gallons less air space > > > On Thursday, December 29, 2016 5:54 PM, "John Thorn th… [at] att.net > [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: > > > > Correction there is 7.48 gal per cubic foot not 8.48 which would make > capacity 23.84 gallons. Old timers moment > > John R Thorn > 479.263.6448 <(479)%20263-6448> > Sent from my iPad > > > >

I agree John R Thorn 479.263.6448

Oh by the way how many gallons Did you want..? On Dec 29, 2016 8:14 PM, "Allen Edwards al… [at] gmail.com [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: > > > OK, let's analyze it. Consider the end. It is a rectangle of height 6.5 > and of unknown length (for now). And a triangle with a height of 4 and a > hypothesis of 13.5. Solving for the missing length we get sqrt(13.5^2 - > 4^2) = 12.894. So the area of the triangle is 25.79. The rectangle is > 83.811. The area of the end is 109.6. This times 48 is 5260.73 sq inches. > > Now, using THIS > <http://letmegooglethat.com/?q=convert+5260.73+cubic+inches+to+gallons> > link, I get 22.77372294, which is pretty close to what I said before. > > On Thu, Dec 29, 2016 at 4:22 PM, Tom Vandiver bs… [at] yahoo.com > [Cal_Boats] <Ca… [at] yahoogroups.com> wrote: > >> >> >> 18.54 gallons less air space >> >> >> On Thursday, December 29, 2016 5:54 PM, "John Thorn th… [at] att.net >> [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: >> >> >> >> Correction there is 7.48 gal per cubic foot not 8.48 which would make >> capacity 23.84 gallons. Old timers moment >> >> John R Thorn >> 479.263.6448 <(479)%20263-6448> >> Sent from my iPad >> >> >> > >

And my analysis assumes these are inside dimensions :-) The real answer is a little more than 20 gallons On Thu, Dec 29, 2016 at 5:16 PM, Edward Stancil <e.… [at] gmail.com> wrote: > Oh by the way how many gallons > Did you want..? > > On Dec 29, 2016 8:14 PM, "Allen Edwards al… [at] gmail.com > [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: > >> >> >> OK, let's analyze it. Consider the end. It is a rectangle of height 6.5 >> and of unknown length (for now). And a triangle with a height of 4 and a >> hypothesis of 13.5. Solving for the missing length we get sqrt(13.5^2 - >> 4^2) = 12.894. So the area of the triangle is 25.79. The rectangle is >> 83.811. The area of the end is 109.6. This times 48 is 5260.73 sq inches. >> >> Now, using THIS >> <http://letmegooglethat.com/?q=convert+5260.73+cubic+inches+to+gallons> >> link, I get 22.77372294, which is pretty close to what I said before. >> >> On Thu, Dec 29, 2016 at 4:22 PM, Tom Vandiver bs… [at] yahoo.com >> [Cal_Boats] <Ca… [at] yahoogroups.com> wrote: >> >>> >>> >>> 18.54 gallons less air space >>> >>> >>> On Thursday, December 29, 2016 5:54 PM, "John Thorn th… [at] att.net >>> [Cal_Boats]" <Ca… [at] yahoogroups.com> wrote: >>> >>> >>> >>> Correction there is 7.48 gal per cubic foot not 8.48 which would make >>> capacity 23.84 gallons. Old timers moment >>> >>> John R Thorn >>> 479.263.6448 <(479)%20263-6448> >>> Sent from my iPad >>> >>> >>> >> >> >

Upper half: 6.5 * 48 * 13.5 = 4212 cu. in. Lower half: (10.5-6.5) * 13.5 * 48 / 2 = 2592 cu. in. Total = 6804 cu. in. divided by 231 cu. in. / gal = 29.455 gallons. You're welcome.

Just to be picky: Rectangular portion: 6.5 * 48 * 13.5 = 4212 cu. in. Angled portion: (10.5-6.5) * 13.5 * 48 / 2 = 1296 cu. in. Total = 5508 cu. in. divided by 231 cu. in. / gal = 23.84 gallons That is if the measurements are inside dimensions. Allen did some subtractions if values are outside dimensions. As others point out, the tank could not be completely filled nor would it drain completely based on where the ports are and how the boat is sitting when the tank is filled. Realistically, the tank is good for 20 to 21 gallons. Cheers Charlie Annapolis From: Ca… [at] yahoogroups.com [mailto:Ca… [at] yahoogroups.com] Sent: Tuesday, January 03, 2017 12:05 AM To: Cal_Boats <Ca… [at] yahoogroups.com> Subject: Re: [Cal_Boats] tankage Upper half: 6.5 * 48 * 13.5 = 4212 cu. in. Lower half: (10.5-6.5) * 13.5 * 48 / 2 = 2592 cu. in. Total = 6804 cu. in. divided by 231 cu. in. / gal = 29.455 gallons. You're welcome.

Also, 13.5 is the Hypotenuse and is not the correct number to use. The long side of the end is about 12.9 outside. Sqrt(13.5^2 - 4^2) = 12.9 Could also subtract about 1/8 gallon for a couple of internal baffles. I still say 20 gallons. Allen On Mon, Jan 2, 2017 at 10:26 PM, 'Charlie Husar' hu… [at] gmail.com [Cal_Boats] <Ca… [at] yahoogroups.com> wrote: > > > Just to be picky: > > > > Rectangular portion: 6.5 * 48 * 13.5 = 4212 cu. in. > > Angled portion: (10.5-6.5) * 13.5 * 48 / 2 = 1296 cu. in. > > Total = 5508 cu. in. divided by 231 cu. in. / gal = 23.84 gallons > > > > That is if the measurements are inside dimensions. Allen did some > subtractions if values are outside dimensions. > > > > As others point out, the tank could not be completely filled nor would it > drain completely based on where the ports are and how the boat is sitting > when the tank is filled. > > > > Realistically, the tank is good for 20 to 21 gallons. > > > > Cheers > > Charlie > > Annapolis > > > > > > *From:* Ca… [at] yahoogroups.com [mailto:Ca… [at] yahoogroups.com] > *Sent:* Tuesday, January 03, 2017 12:05 AM > *To:* Cal_Boats <Ca… [at] yahoogroups.com> > *Subject:* Re: [Cal_Boats] tankage > > > > > > > Upper half: 6.5 * 48 * 13.5 = 4212 cu. in. > > Lower half: (10.5-6.5) * 13.5 * 48 / 2 = 2592 cu. in. > > Total = 6804 cu. in. divided by 231 cu. in. / gal = 29.455 gallons. > > You're welcome. > > > > > >

Right again, Allen. I botched that part of the correction. Take Care Charlie From: Allen Edwards [mailto:al… [at] gmail.com] Sent: Tuesday, January 03, 2017 1:30 AM To: Ca… [at] yahoogroups.com; Charlie Husar <hu… [at] gmail.com> Subject: Re: [Cal_Boats] tankage Also, 13.5 is the Hypotenuse and is not the correct number to use. The long side of the end is about 12.9 outside. Sqrt(13.5^2 - 4^2) = 12.9 Could also subtract about 1/8 gallon for a couple of internal baffles. I still say 20 gallons. Allen On Mon, Jan 2, 2017 at 10:26 PM, 'Charlie Husar' hu… [at] gmail.com <mailto:hu… [at] gmail.com> [Cal_Boats] <Ca… [at] yahoogroups.com <mailto:Ca… [at] yahoogroups.com> > wrote: Just to be picky: Rectangular portion: 6.5 * 48 * 13.5 = 4212 cu. in. Angled portion: (10.5-6.5) * 13.5 * 48 / 2 = 1296 cu. in. Total = 5508 cu. in. divided by 231 cu. in. / gal = 23.84 gallons That is if the measurements are inside dimensions. Allen did some subtractions if values are outside dimensions. As others point out, the tank could not be completely filled nor would it drain completely based on where the ports are and how the boat is sitting when the tank is filled. Realistically, the tank is good for 20 to 21 gallons. Cheers Charlie Annapolis From: Ca… [at] yahoogroups.com <mailto:Ca… [at] yahoogroups.com> [mailto:Ca… [at] yahoogroups.com <mailto:Ca… [at] yahoogroups.com> ] Sent: Tuesday, January 03, 2017 12:05 AM To: Cal_Boats <Ca… [at] yahoogroups.com <mailto:Ca… [at] yahoogroups.com> > Subject: Re: [Cal_Boats] tankage Upper half: 6.5 * 48 * 13.5 = 4212 cu. in. Lower half: (10.5-6.5) * 13.5 * 48 / 2 = 2592 cu. in. Total = 6804 cu. in. divided by 231 cu. in. / gal = 29.455 gallons. You're welcome.